Daily challenge for 2026-04-08
463. Smallest Square Root Ceiling
Given a non-negative integer n, find the smallest integer x such that x * x is greater than or equal to n. This is equivalent to finding the ceiling of the square root of n. You should solve this using a binary search approach to maintain efficiency.
Example:Input: n = 8Output: 3
(Because 2*2=4 is less than 8, but 3*3=9 is greater than or equal to 8).
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